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Updated SC2091 (markdown)

koalaman
2015-04-29 09:51:18 -07:00
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SC2091.md

@@ -26,6 +26,8 @@ The problem is when you use `$(date +%F)` alone as a command. Bash evaluates the
Sometimes this results in this confounding `command not found` messages. Other times you get even stranger issues, like the example problematic code which always evaluates to false.
The solution is simply to remove the surrounding `$()`. This will execute the command instead of the command's output.
### Exceptions:
If you really want to execute the output of a command rather than the command itself, you can ignore this message.