From d7a155e77dccf9ecfaa83389ce2d82335aad547a Mon Sep 17 00:00:00 2001
From: koalaman <vidar@vidarholen.net>
Date: Thu, 25 Jan 2018 19:29:07 -0800
Subject: [PATCH] Updated SC2051 (markdown)

---
 SC2051.md | 9 ++++++++-
 1 file changed, 8 insertions(+), 1 deletion(-)

diff --git a/SC2051.md b/SC2051.md
index 063c87e..0a2d417 100644
--- a/SC2051.md
+++ b/SC2051.md
@@ -24,18 +24,25 @@ In Bash, brace expansion happens before variable expansion. This means that brac
 
 For integers, use an arithmetic for loop instead. For zero-padded numbers or letters, use of eval may be warranted:
 
+```bash
 from="a" to="m"
 for c in $(eval "echo {$from..$to}"); do echo "$c"; done
+```
 
 or more carefully (if `from`/`to` could be user input, or if the brace expansion could have spaces):
 
+```bash
 from="a" to="m"
 while IFS= read -d '' -r c
 do
   echo "Read $c"
 done <  <(eval "printf '%s\0' $(printf "{%q..%q}.jpg" "$from" "$to")")
-
+```
 
 ### Exceptions
 
 None (if you're writing for e.g. zsh, make sure the shebang indicates this so shellcheck won't warn)
+
+### Related Resources:
+
+* [StackOverflow: Variables in bash seq replacement ({1..10})](https://stackoverflow.com/questions/169511/how-do-i-iterate-over-a-range-of-numbers-defined-by-variables-in-bash)
\ No newline at end of file