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## `[ ]` does not apply arithmetic evaluation. Evaluate with `$((..))` for numbers, or use string comparator for strings.
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### Problematic code:
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```sh
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[ 2*3 -eq array[i] ]
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```
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### Correct code:
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```sh
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[ $((2*3)) -eq $((array[i])) ]
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```
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### Rationale:
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When using `[[ .. ]]` with numerical comparators (`-eq`, `-lt`, etc), the value on either side will be evaluated as an arithmetic expression. This means that `2*3` will be evaluated to `6`, and `x` will be evaluated to the contents of the variable `$x`.
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When using `[ .. ]`, this does not happen. `2*3` and `x` will both be considered invalid numbers. Instead, use e.g. `$((2*3))` to evaluate the expression before passing it to `[ .. ]`.
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Alternatively, if the expression should be considered a string, quote the expression and use a string comparison operator like `=` and `!=`.
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### Exceptions:
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None
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### Related resources:
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* Help by adding links to BashFAQ, StackOverflow, man pages, POSIX, etc!
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