From 4e5ab8ab046f1a7fd9f60189cace0610a08e1e8e Mon Sep 17 00:00:00 2001
From: Vidar Holen <vidar@vidarholen.net>
Date: Sat, 23 Jun 2018 22:53:27 -0700
Subject: [PATCH] Updated SC1001 (markdown)

---
 SC1001.md | 12 +++---------
 1 file changed, 3 insertions(+), 9 deletions(-)

diff --git a/SC1001.md b/SC1001.md
index d50f7e8..fd31a56 100644
--- a/SC1001.md
+++ b/SC1001.md
@@ -6,11 +6,8 @@
 # Want literal backslash
 echo Yay \o/
 
-# Want linefeed
-greeting=Hello\nWorld
-
 # Want other characters
-carriagereturn=\r
+bell=\a
 ```
 
 ### Correct code:
@@ -18,10 +15,7 @@ carriagereturn=\r
 ```sh
 echo 'Yay \o/'
 
-greeting='Hello
-World'
-
-carriagereturn=$(printf '\r')
+bell="$(printf '\a')"
 ```
 
 ### Rationale:
@@ -30,7 +24,7 @@ You have escaped something that has no special meaning when escaped. The backsla
 
 If the backslash was supposed to be literal, single quote or escape it.
 
-If you wanted it to expand to something, rewrite the expression. For linefeeds (`\n`), put them literally in quotes. For other characters, use POSIX `printf` or bash/ksh `$'...'`. 
+If you wanted it to expand to something, rewrite the expression to use `printf` (or in bash, `$'\t'`). If the sequence in question is `\n`, `\t` or `\r`, you instead get a [[SC1012]] that describes this. 
 
 ### Exceptions