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-# Use `$(...)` notation instead of legacy backticked `` `...` ``.
-
-### Problematic code
-
-```sh
-echo "You are running on `uname`"
-```
-
-### Correct code
-
-```sh
-echo "You are running on $(uname)"
-```
-
-### Rationale
-
-Backtick command substitution `` `...` `` is legacy syntax with several issues.
-
-1. It has a series of undefined behaviors related to quoting in POSIX.
-1. It imposes a custom escaping mode with surprising results.
-1. It's exceptionally hard to nest.
-
-`$(...)` command substitution has none of these problems, and is therefore strongly encouraged.
-
-### Exceptions
-
-None.
-
-### Related resources:
-
-* [BashFaq: Why is `$(...)` preferred over `` `...` `` (backticks)?](http://mywiki.wooledge.org/BashFAQ/082)
-* [StackOverflow: What is the difference between $(command) and `` `command` `` in shell programming?](https://stackoverflow.com/questions/4708549/shell-programming-whats-the-difference-between-command-and-command)
-* [shfmt](https://github.com/mvdan/sh) will automatically convert the legacy syntax
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